3[3-(2-4x)]+2x=2(7x+3)-3

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Solution for 3[3-(2-4x)]+2x=2(7x+3)-3 equation:


Simplifying
3[3 + -1(2 + -4x)] + 2x = 2(7x + 3) + -3
3[3 + (2 * -1 + -4x * -1)] + 2x = 2(7x + 3) + -3
3[3 + (-2 + 4x)] + 2x = 2(7x + 3) + -3

Combine like terms: 3 + -2 = 1
3[1 + 4x] + 2x = 2(7x + 3) + -3
[1 * 3 + 4x * 3] + 2x = 2(7x + 3) + -3
[3 + 12x] + 2x = 2(7x + 3) + -3

Combine like terms: 12x + 2x = 14x
3 + 14x = 2(7x + 3) + -3

Reorder the terms:
3 + 14x = 2(3 + 7x) + -3
3 + 14x = (3 * 2 + 7x * 2) + -3
3 + 14x = (6 + 14x) + -3

Reorder the terms:
3 + 14x = 6 + -3 + 14x

Combine like terms: 6 + -3 = 3
3 + 14x = 3 + 14x

Add '-3' to each side of the equation.
3 + -3 + 14x = 3 + -3 + 14x

Combine like terms: 3 + -3 = 0
0 + 14x = 3 + -3 + 14x
14x = 3 + -3 + 14x

Combine like terms: 3 + -3 = 0
14x = 0 + 14x
14x = 14x

Add '-14x' to each side of the equation.
14x + -14x = 14x + -14x

Combine like terms: 14x + -14x = 0
0 = 14x + -14x

Combine like terms: 14x + -14x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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